CuO + 2HNO3 -> Cu(NO3)2 + H2O
3Cu + 8HNO3 -> 3Cu(NO3)2 + 2NO + 4H2O
a. nNO=0,1 mol
=>nCu=0,1.3/2=0,15 mol
mCu=0,15.64=9,6g
mCuO=17,6-9,6=8 g
%mCuO=8/17,6.100%=45,45%
%mCu=100%-45,45%=54,55%
b. nCu(NO3)2 =nCuO+nCu=8/80+0,15=0,25 mol
mCu(NO3)2=0,25.188=47g
CM Cu(NO3)2=0,25/2=0,125M