3^x + 4 . 3^x-2 = 333 3x + 15 chia hết cho x + 2

c. To solve the equation 3^x + 4 . 3^(x-2) = 333, we can simplify it first by using the properties of exponents.

We know that 3^(x-2) can be written as 3^x / 3^2, which is equal to 3^x / 9.

So the equation becomes: 3^x + 4 . (3^x / 9) = 333.

Multiplying both sides of the equation by 9 to eliminate the fraction, we get: 9 . 3^x + 4 . 3^x = 2997.

Combining like terms, we have: 13 . 3^x = 2997.

Dividing both sides of the equation by 13, we get: 3^x = 2997 / 13.

Taking the logarithm of both sides of the equation, we have: x . log(3) = log(2997 / 13).

Dividing both sides of the equation by log(3), we get: x = log(2997 / 13) / log(3).

Using a calculator, we can find the approximate value of x.

d. To solve the equation 3x + 15 divided by (x + 2) = 0, we can set the numerator equal to zero.

So we have: 3x + 15 = 0.

Subtracting 15 from both sides of the equation, we get: 3x = -15.

Dividing both sides of the equation by 3, we get: x = -15 / 3.

Simplifying, we have: x = -5.

Therefore, x = -5 is the solution to the equation.