Giải phương trình lượng giác

To solve the equation 2sin2x - sin4x = 0, we can factor out sin2x:

sin2x(2 - sin2x) = 0

Now we have two possibilities:

1) sin2x = 0
If sin2x = 0, then 2x = 0 or 2x = π.
So the solutions for this case are x = 0 and x = π/2.

2) 2 - sin2x = 0
If 2 - sin2x = 0, then sin2x = 2, which is not possible since the range of sine function is -1 to 1.

Therefore, the solutions to the equation 2sin2x - sin4x = 0 are x = 0 and x = π/2.