To simplify the expression [2^2023:2^2022 - 3.(5.4-10)+2020^0], we can follow the order of operations (PEMDAS/BODMAS):

First, let's simplify the exponentiation:
2^2023 = 2 * 2 * 2 * ... * 2 (2023 times)
2^2022 = 2 * 2 * 2 * ... * 2 (2022 times)

Since we are dividing 2^2023 by 2^2022, we can cancel out one of the 2's:
2^2023 / 2^2022 = 2^(2023-2022) = 2^1 = 2

Next, let's simplify the multiplication and subtraction inside the parentheses:
5.4 - 10 = -4.6

Now, let's simplify the multiplication outside the parentheses:
3 * (-4.6) = -13.8

Finally, let's simplify 2020^0:
Any number (except 0) raised to the power of 0 is equal to 1.
So, 2020^0 = 1

Now, let's put it all together:
[2^2023:2^2022 - 3.(5.4-10)+2020^0] = [2:1 - (-13.8) + 1] = [2 - (-13.8) + 1] = [2 + 13.8 + 1] = 16.8