Tham khảo câu trả lời từ Trợ lý ảo Lazi b) To simplify the expression x+1/x^2-x + x+2/1-x^2, we need to find a common denominator for both fractions. The common denominator is (x^2 - x)(1 - x^2). The first fraction can be multiplied by (1 - x^2)/(1 - x^2) to get (x(1 - x^2) + (x + 1))/(x^2 - x)(1 - x^2). The second fraction can be multiplied by (x^2 - x)/(x^2 - x) to get ((x + 2)(x^2 - x))/(x^2 - x)(1 - x^2). Combining the two fractions, we have (x(1 - x^2) + (x + 1) + (x + 2)(x^2 - x))/(x^2 - x)(1 - x^2). Simplifying the numerator, we get (x - x^3 + x + 1 + x^3 + x^2 - 2x)/(x^2 - x)(1 - x^2). Combining like terms, we have (2x^2)/(x^2 - x)(1 - x^2). Therefore, the simplified expression is 2x^2/(x^2 - x)(1 - x^2). c) To simplify the expression 2x+1/4x-2 + 1-2x/4x+2 - 2/1-4x^2, we need to find a common denominator for all the fractions. The common denominator is (4x - 2)(4x + 2)(1 - 4x^2). The first fraction can be multiplied by (4x + 2)(1 - 4x^2)/((4x + 2)(1 - 4x^2)) to get ((2x(4x + 2) + (1 - 2x)(1 - 4x^2))/((4x - 2)(4x + 2)(1 - 4x^2)). The second fraction can be multiplied by (4x - 2)(1 - 4x^2)/((4x - 2)(1 - 4x^2)) to get ((1 - 2x)(4x - 2)(1 - 4x^2))/((4x - 2)(4x + 2)(1 - 4x^2)). The third fraction can be multiplied by (4x - 2)(4x + 2)/((4x - 2)(4x + 2)) to get (-2(4x - 2)(4x + 2))/((4x - 2)(4x + 2)(1 - 4x^2)). Combining the three fractions, we have ((2x(4x + 2) + (1 - 2x)(1 - 4x^2)) + (1 - 2x)(4x - 2)(1 - 4x^2) - 2(4x - 2)(4x + 2))/((4x - 2)(4x + 2)(1 - 4x^2)). Simplifying the numerator, we get (8x^2 + 4x + 1 - 8x^3 - 4x + 2x - 4x^3 + 2 - 8x^2 - 4x + 16x^2 - 8)/((4x - 2)(4x + 2)(1 - 4x^2)). Combining like terms, we have (-12x^3 + 16x^2 - 2)/((4x - 2)(4x + 2)(1 - 4x^2)). Therefore, the simplified expression is (-12x^3 + 16x^2 - 2)/((4x - 2)(4x + 2)(1 - 4x^2)). d) To simplify the expression 3x-y/x-5 - 2x-3y/2y+5, we need to find a common denominator for both fractions. The common denominator is (x - 5)(2y + 5). The first fraction can be multiplied by (2y + 5)/(2y + 5) to get ((3x - y)(2y + 5))/((x - 5)(2y + 5)). The second fraction can be multiplied by (x - 5)/(x - 5) to get ((2x - 3y)(x - 5))/((x - 5)(2y + 5)). Combining the two fractions, we have ((3x - y)(2y + 5) - (2x - 3y)(x - 5))/((x - 5)(2y + 5)). Simplifying the numerator, we get (6xy + 15x - 2y^2 - 5y - 2x^2 + 10x - 3xy + 15y)/((x - 5)(2y + 5)). Combining like terms, we have (3xy + 25x - 2y^2 + 10y - 2x^2)/((x - 5)(2y + 5)). Therefore, the simplified expression is (3xy + 25x - 2y^2 + 10y - 2x^2)/((x - 5)(2y + 5)).