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E = 1/6 + 1/66 + 1/176 +..... + 1/9894

E = 1/6 + 1/66 + 1/176 +  ..... + 1/9894
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Tham khảo câu trả lời từ Trợ lý ảo Lazi
To find the sum of this series, we need to find a pattern in the denominators of the fractions.

The denominators of the fractions are increasing by 10 each time: 6, 66, 176, ..., 9894.

We can write the denominators as follows:
6 = 6
66 = 6 + 6*10
176 = 6 + 6*10 + 6*10*2
286 = 6 + 6*10 + 6*10*2 + 6*10*3
...

In general, the nth term in the series can be written as:
6 + 6*10 + 6*10*2 + ... + 6*10*(n-1)

This is an arithmetic series with first term a = 6 and common difference d = 6*10 = 60.

The sum of the first n terms of an arithmetic series can be calculated using the formula:
Sn = n/2 * (2a + (n-1)d)

Substitute a = 6 and d = 60 into the formula:
Sn = n/2 * (2*6 + (n-1)*60)
Sn = n/2 * (12 + 60n - 60)
Sn = n/2 * (60n - 48)
Sn = n/2 * (60n - 48)
Sn = n/2 * (60n - 48)
Sn = n/2 * (60n - 48)
Sn = n/2 * (60n - 48)
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