To calculate the sum \( D \), we need to evaluate the series given in the image:

\[ D = \frac{2^2}{1.3} + \frac{2^2}{3.5} + \frac{2^2}{5.7} + \cdots + \frac{2^2}{99.101} \]

First, let's simplify the numerator \( 2^2 \):

\[ 2^2 = 4 \]

So the series becomes:

\[ D = \frac{4}{1.3} + \frac{4}{3.5} + \frac{4}{5.7} + \cdots + \frac{4}{99.101} \]

Now, let's calculate each term individually:

1. \(\frac{4}{1.3} \approx 3.08\)
2. \(\frac{4}{3.5} \approx 1.14\)
3. \(\frac{4}{5.7} \approx 0.70\)
4. \(\frac{4}{99.101} \approx 0.04\)

Adding these values together:

\[ 3.08 + 1.14 + 0.70 + \cdots + 0.04 \]

Since the series is long and the terms decrease rapidly, the sum will converge to a certain value. However, without more terms or a specific pattern, it's challenging to provide an exact sum. For a more accurate result, consider using numerical methods or software tools to sum the series.