It looks like you've provided two equations. However, it appears there was a bit of confusion with the text formatting, as it's repeated and partially overlaps. I'll clarify the two equations:

1. \( 3x + 2y = 6 \)
2. \( x - 3y = 2 \)

Let's solve this system of equations step by step.

### Step 1: Solve one of the equations for one variable

Let's solve the second equation for \( x \):

\[
x = 3y + 2
\]

### Step 2: Substitute into the first equation

Now, substitute \( x \) into the first equation:

\[
3(3y + 2) + 2y = 6
\]

Expanding this gives:

\[
9y + 6 + 2y = 6
\]

Combining like terms:

\[
11y + 6 = 6
\]

### Step 3: Solve for \( y \)

Subtract \( 6 \) from both sides:

\[
11y = 0
\]

Dividing by \( 11 \):

\[
y = 0
\]

### Step 4: Substitute \( y \) back to find \( x \)

Now substitute \( y \) back into the equation we used to express \( x \):

\[
x = 3(0) + 2 = 2
\]

### Final solution

The solution to the system of equations is:

\[
x = 2, \quad y = 0
\]

You can verify this by substituting these values back into both original equations.