It looks like you are trying to solve the quadratic equation \(3x^2 - 7x - 10 = 0\). We can use the quadratic formula to find the values of \(x\):

\[
x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a}
\]

For the equation \(3x^2 - 7x - 10 = 0\), the coefficients are:
- \(a = 3\)
- \(b = -7\)
- \(c = -10\)

Let's plug these values into the quadratic formula.

First, calculate the discriminant:

\[
b^2 - 4ac = (-7)^2 - 4(3)(-10) = 49 + 120 = 169
\]

Now, plug the values into the formula:

\[
x = \frac{{-(-7) \pm \sqrt{169}}}{2(3)} = \frac{6}
\]

Now, we will find the two possible solutions:

1. \(x = \frac{6} = \frac{20}{6} = \frac{10}{3}\)
2. \(x = \frac{6} = \frac{-6}{6} = -1\)

Thus, the solutions to the equation \(3x^2 - 7x - 10 = 0\) are:

\[
x = \frac{10}{3} \quad \text{and} \quad x = -1
\]