Cho P = √x / √x - 2. Tìm |P| > P

To solve the equation \( P = \frac{\sqrt{x}}{\sqrt{x} - 2} \) and find conditions satisfying \( |P| > P \), we can start with the following steps:

1. **Analyze the expression for \( P \)**:
\[
P = \frac{\sqrt{x}}{\sqrt{x} - 2}
\]
The expression is defined for \( \sqrt{x} - 2 \neq 0 \), which means \( \sqrt{x} \neq 2 \) or \( x \neq 4 \).

2. **Condition for \( |P| > P \)**:
The inequality \( |P| > P \) implies two possible cases:
- Case 1: \( P > 0 \)
- Case 2: \( P < 0 \)

If \( P > 0 \):
\[
|P| = P \Rightarrow |P| > P \text{ is not possible.}
\]

If \( P < 0 \):
\[
|P| = -P \Rightarrow -P > P \Rightarrow 0 > 2P \Rightarrow P < 0
\]

3. **Find the domain where \( P < 0 \)**:
For \( P < 0 \):
\[
\frac{\sqrt{x}}{\sqrt{x} - 2} < 0
\]
This occurs when:
- \( \sqrt{x} < 0 \) (not valid since \( \sqrt{x} \geq 0 \))
- \( \sqrt{x} - 2 < 0 \Rightarrow \sqrt{x} < 2 \Rightarrow x < 4 \)

Thus, \( P < 0 \) when \( x \) is in the interval \( [0, 4) \).

4. **Final Result**:
Therefore, the conditions for \( |P| > P \) are satisfied when:
\[
0 \leq x < 4
\]

These steps will lead you to the needed answer. If you need help with the other equations or problems from your notes, let me know!