Let's simplify the expression you provided step by step:

The expression is:
\[
\frac{1}{x} + 1 + \frac{1}{1-x} + \frac{2x^2}{x^2} - \frac{11}{x} + 1 + \frac{1}{1-x} + \frac{2x^2}{x^2} - 1
\]

First, simplify terms where possible:

1. The term \(\frac{2x^2}{x^2} = 2\).
2. Now, combine the simplified terms:
\[
\frac{1}{x} + 1 + \frac{1}{1-x} + 2 - \frac{11}{x} + 1 + \frac{1}{1-x} + 2 - 1
\]

3. Combine all the constants:
\[
1 + 2 + 1 + 2 - 1 = 5
\]

4. Now, combine the fractions:
\[
\frac{1}{x} - \frac{11}{x} + \frac{1}{1-x} + \frac{1}{1-x}
\]
\[
= \frac{1 - 11}{x} + 2 \cdot \frac{1}{1-x}
\]
\[
= \frac{-10}{x} + \frac{2}{1-x}
\]

5. Now, combine all parts:
\[
= 5 + \frac{-10}{x} + \frac{2}{1-x}
\]

Now, we can express the simplified form as follows:
\[
5 - \frac{10}{x} + \frac{2}{1-x}
\]

To combine the fraction terms, you may want to find a common denominator, which would be \(x(1-x)\).

So the final expression would be:
\[
5 - \frac{10(1-x)}{x(1-x)} + \frac{2x}{x(1-x)}
\]
\[
= 5 - \frac{10 - 10x + 2x}{x(1-x)}
\]
\[
= 5 - \frac{10 - 8x}{x(1-x)}
\]

Thus, the expression is:
\[
5 - \frac{10 - 8x}{x(1-x)}
\]

This is a simplified form. You can manipulate this further by combining the terms based on your requirements.