pt chuyen dong cua hòn đá va hon thep la:
x1=1/2gt^2=4.9t^2
x2=15t+4.9t^2
ta lai co
t1=1.277s
x2=vt2+at2^2/2
==> t2=0.463s
2 vat roi cach nhau khong thoi gjan la
t1-t2= 0.814
pt chuyen dong cua hon` da va hon thep la:
x1=1/2gt^2=4.9t^2
x2=15t+4.9t^2
ta lai co
t1=1.277s
x2=vt2+at2^2/2
==> t2=0.463s
2 vat roi cach nhau khong thoi gjan la
t1-t2= 0.814