X mũ 2+2y=xy

To solve the equation x^2 + 2y = xy, we can rearrange it to the form x^2 - xy + 2y = 0.

Now, let's treat this equation as a quadratic equation in terms of x. We can use the quadratic formula to solve for x:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 1, b = -y, and c = 2y. Substituting these values into the quadratic formula, we get:

x = (y ± √(y^2 - 4y)) / 2

Simplifying further, we have:

x = (y ± √(y(y - 4))) / 2

Therefore, the solutions for x in terms of y are:

x = (y + √(y(y - 4))) / 2
x = (y - √(y(y - 4))) / 2