10x-x^2-16=0   Dk x>0

To solve the equation 10x - x^2 - 16 = 0, we can rearrange it to the form of a quadratic equation:

x^2 - 10x + 16 = 0

Now, we can factorize the quadratic equation:

(x - 2)(x - 8) = 0

Setting each factor equal to zero, we have:

x - 2 = 0 or x - 8 = 0

Solving for x in each equation, we get:

x = 2 or x = 8

Since we are given that x > 0, the only solution that satisfies this condition is x = 8.