To find the quotient and remainder when (3n+7) is divided by (n-2), we can use polynomial long division.

Let's start by dividing the first term of the numerator by the first term of the denominator:

3n / n = 3

Now, multiply this result by the entire denominator:

3 * (n-2) = 3n - 6

Subtract this result from the numerator:

(3n + 7) - (3n - 6) = 13

Since the degree of the numerator (1) is less than the degree of the denominator (1), we have our final quotient and remainder:

Quotient: 3
Remainder: 13