Rút gọn sin^2x-tan^2x/cos^2x-cot^2x Tham khảo câu trả lời từ Trợ lý ảo Lazi To simplify the expression sin^2x_tan^2x/cos^2x-cot^2x, we can start by simplifying the individual terms. First, let's simplify sin^2x_tan^2x. We know that tan^2x = sin^2x/cos^2x, so we can substitute this into the expression: sin^2x_tan^2x = sin^2x * (sin^2x/cos^2x) = sin^4x/cos^2x Next, let's simplify cos^2x-cot^2x. We know that cot^2x = cos^2x/sin^2x, so we can substitute this into the expression: cos^2x-cot^2x = cos^2x - (cos^2x/sin^2x) = cos^2x - cos^2x/sin^2x To simplify further, we can find a common denominator for the two terms: cos^2x - cos^2x/sin^2x = (cos^2x * sin^2x - cos^2x) / sin^2x Now, let's simplify the numerator: (cos^2x * sin^2x - cos^2x) = cos^2x * (sin^2x - 1) Finally, we can substitute the simplified terms back into the original expression: sin^4x/cos^2x - (cos^2x * (sin^2x - 1)) / sin^2x Now, we can simplify further by finding a common denominator for the two terms: (sin^4x * sin^2x - cos^2x * (sin^2x - 1)) / (cos^2x * sin^2x) Next, let's simplify the numerator: (sin^4x * sin^2x - cos^2x * (sin^2x - 1)) = sin^6x - cos^2x * sin^2x + cos^2x Finally, we can substitute the simplified terms back into the original expression: (sin^6x - cos^2x * sin^2x + cos^2x) / (cos^2x * sin^2x) And that is the simplified expression.