To solve the expression \(-\frac{1}{5} + \frac{5}{7} - \frac{7}{9} - \frac{11}{13} - \frac{13}{15} + \frac{11}{13} - \frac{11}{13} - \frac{9}{11} + \frac{7}{9} - \frac{5}{7}\), we can simplify it step by step.

First, let's combine like terms where possible:

1. Combine \(\frac{11}{13}\) terms:
\[
\frac{11}{13} - \frac{11}{13} - \frac{11}{13} = -\frac{11}{13}
\]

2. Combine \(\frac{7}{9}\) terms:
\[
-\frac{7}{9} + \frac{7}{9} = 0
\]

3. Combine \(\frac{5}{7}\) terms:
\[
\frac{5}{7} - \frac{5}{7} = 0
\]

Now, rewrite the expression with the combined terms:
\[
-\frac{1}{5} - \frac{11}{13} - \frac{13}{15} - \frac{9}{11}
\]

Next, let's find a common denominator to combine these fractions. The least common multiple (LCM) of the denominators \(5, 13, 15,\) and \(11\) is \(5 \times 13 \times 3 \times 11 = 2145\).

Convert each fraction to have the common denominator of 2145:

1. \(-\frac{1}{5}\):
\[
-\frac{1}{5} = -\frac{1 \times 429}{5 \times 429} = -\frac{429}{2145}
\]

2. \(-\frac{11}{13}\):
\[
-\frac{11}{13} = -\frac{11 \times 165}{13 \times 165} = -\frac{1815}{2145}
\]

3. \(-\frac{13}{15}\):
\[
-\frac{13}{15} = -\frac{13 \times 143}{15 \times 143} = -\frac{1859}{2145}
\]

4. \(-\frac{9}{11}\):
\[
-\frac{9}{11} = -\frac{9 \times 195}{11 \times 195} = -\frac{1755}{2145}
\]

Now, add these fractions together:
\[
-\frac{429}{2145} - \frac{1815}{2145} - \frac{1859}{2145} - \frac{1755}{2145}
\]

Combine the numerators:
\[
-\frac{429 + 1815 + 1859 + 1755}{2145} = -\frac{5858}{2145}
\]

Simplify the fraction if possible. The greatest common divisor (GCD) of 5858 and 2145 is 1, so the fraction is already in its simplest form.

Thus, the simplified result is:
\[
-\frac{5858}{2145}
\]