It seems like you're trying to solve an equation involving \( x \). However, the way it's presented is a bit unclear. Let's break it down.

You seem to have two parts:

1. \( \frac{120}{x - 5} = 201 \)
2. \( \frac{20}{x - 5} = 20 \)

Let's solve each equation separately.

### For the first equation:
\[
\frac{120}{x - 5} = 201
\]

To solve for \( x \), multiply both sides by \( (x - 5) \):
\[
120 = 201(x - 5)
\]

Expanding the right side:
\[
120 = 201x - 1005
\]

Rearranging gives:
\[
201x = 120 + 1005
\]
\[
201x = 1125
\]

Dividing both sides by 201:
\[
x = \frac{1125}{201} \approx 5.59
\]

### For the second equation:
\[
\frac{20}{x - 5} = 20
\]

Again, multiply both sides by \( (x - 5) \):
\[
20 = 20(x - 5)
\]

Expanding:
\[
20 = 20x - 100
\]

Rearranging gives:
\[
20x = 20 + 100
\]
\[
20x = 120
\]

Dividing both sides by 20:
\[
x = \frac{120}{20} = 6
\]

### Summary of Solutions:
1. For \( \frac{120}{x - 5} = 201\), \( x \approx 5.59 \)
2. For \( \frac{20}{x - 5} = 20\), \( x = 6 \)

Please clarify if you intended these to be connected in some way or if they represent separate equations, or if there's more to the question!