|x+(1)/(1*2*3)|+|x+(1)/(2*3*4)|+|x+(1)/(3*4*5)|+....+|x+(1)/(18+19+10)|-19x

To simplify the expression provided, let's first break it down into parts.

1. **Understanding the Series**:
- The expression inside the absolute value signs consists of terms of the form \( |x + \frac{1}{n(n+1)(n+2)}| \) for \( n = 1, 2, \ldots, 18 \).
- Thus, the series can be written as:
\[
S = \sum_{n=1}^{18} |x + \frac{1}{n(n+1)(n+2)}|
\]

2. **The Full Expression**:
- We are asked to evaluate:
\[
S - 19x.
\]
Given:
\[
S = \sum_{n=1}^{18} |x + \frac{1}{n(n+1)(n+2)}|
\]

3. **Structure of the Series**:
Each term \( \frac{1}{n(n+1)(n+2)} \) can be computed separately.

4. **Behavior of \( S \)**:
- The terms \( \frac{1}{n(n+1)(n+2)} \) get smaller as \( n \) increases.
- The first term is \( \frac{1}{1 \cdot 2 \cdot 3} = \frac{1}{6} \) and the last term for \( n=18 \) results in \( \frac{1}{18 \cdot 19 \cdot 20} \).

5. **Assumption**:
- To simplify, let's analyze what happens when \( x \) is sufficiently large or sufficiently small.

6. **Final Formulation**:
- The entire expression simplifies to:
\[
S - 19x = \sum_{n=1}^{18} |x + \frac{1}{n(n+1)(n+2)}| - 19x
\]
- Depending on whether \( x \) is positive or negative, the evaluation for absolute values will vary.

7. **Conclusion**:
The final resolution will depend on the value of \( x \). In a directive context where \( x \) might not have restrictions, the expression represents the absolute differences conditioned upon the nature of \( x \) (whether it exceeds or not the small increments given through those terms).

Evaluating or simplifying any further requires specific values of \( x \). However, for most analytical purposes, we can denote the expression as:
\[
E(x) = \sum_{n=1}^{18} |x + \frac{1}{n(n+1)(n+2)}| - 19x.
\]

For any specific \( x \), the next step would be to evaluate this expression numerically or symbolically depending on constraints.