Cho phản ứng dưới đây phản ứng nào là phản ứng oxi hóa khử

$$\begin{gathered} \mathrm{Câu} 1: \mathrm{Cho} \mathrm{phản} \mathrm{ứng} \mathrm{nào} \mathrm{dưới} \mathrm{đây} \mathrm{là} \mathrm{phản} \mathrm{ứng} \mathrm{oxi} \mathrm{hóa} -\mathrm{khử} \\ \mathrm{A}.{\mathrm{Cl}}_2+\mathrm{NaOH}\to \mathrm{NaClO}+\mathrm{NaCl}+{\mathrm{H}}_2\mathrm{O} \\ \mathrm{B}. \mathrm{HCl}+\mathrm{NaOH}\to \mathrm{NaCl}+{\mathrm{H}}_2\mathrm{O} \\ \mathrm{C}. {\mathrm{Na}}_2{\mathrm{CO}}_3+{\mathrm{CaCl}}_2\to {\mathrm{CaCO}}_3+\mathrm{NaCl} \\ \mathrm{D}. \mathrm{Ca}{\left(\mathrm{OH}\right)}_2+{\mathrm{CO}}_2\to {\mathrm{CaCO}}_3+{\mathrm{H}}_2\mathrm{O} \\ \mathrm{Câu} 2: \mathrm{Cho} \mathrm{phản} \mathrm{ứng} \mathrm{sau} \mathrm{đây} \mathrm{xảy} \mathrm{ra} \mathrm{trong} \mathrm{dung} \mathrm{dịch}: \\ 10{\mathrm{FeSO}}_4+2{\mathrm{KMnO}}_4+8{\mathrm{H}}_2{\mathrm{SO}}_4\to 5{\mathrm{Fe}}_2{\left({\mathrm{SO}}_4\right)}_3+{\mathrm{K}}_2{\mathrm{SO}}_4+2{\mathrm{MnSO}}_4+8{\mathrm{H}}_2\mathrm{O} \\ \mathrm{vai} \mathrm{trò} \mathrm{của} {\mathrm{FeSO}}_4 \mathrm{là} \\ \mathrm{A}. \mathrm{Chất} \mathrm{khử} \mathrm{B}.\mathrm{axit} \mathrm{C}.\mathrm{môi} \mathrm{trường} \mathrm{D}.\mathrm{chất} \mathrm{oxi} \mathrm{hóa} \\ \mathrm{Câu} 3: \mathrm{Trong} \mathrm{các} \mathrm{phản} \mathrm{ứng} \mathrm{dưới} \mathrm{đây}, \mathrm{phản} \mathrm{ứng} \mathrm{nào} \mathrm{không} \mathrm{phải} \mathrm{là} \\ \mathrm{phản} \mathrm{ứng} \mathrm{oxi} \mathrm{hóa}-\mathrm{khử} : \\ \mathrm{A}.\mathrm{Zn}+2\mathrm{HCl}\to {\mathrm{ZnCl}}_2+{\mathrm{H}}_2 \mathrm{B}. 2\mathrm{Mg}+{\mathrm{O}}_2\to 2\mathrm{MgO} \\ \mathrm{C}.\mathrm{ZnS}+2\mathrm{HCl}\to {\mathrm{ZnCl}}_2+{\mathrm{H}}_2\mathrm{S} \mathrm{D}.\mathrm{Fe}+{\mathrm{CuSO}}_4\to {\mathrm{FeSO}}_4+\mathrm{Cu} \\ \mathrm{Câu} 4:\mathrm{Nguyên} \mathrm{tử} \mathrm{của} \mathrm{nguyên} \mathrm{tố} \mathrm{X} \mathrm{có} \mathrm{electron} \mathrm{phân} \mathrm{lớp} \mathrm{ngoài} \mathrm{cùng} \mathrm{dạng} \\ {\mathrm{np}}^{(2\mathrm{n}+1)}(\mathrm{n} \mathrm{là} \mathrm{số} \mathrm{lớp} \mathrm{electron}). \mathrm{Số} \mathrm{electron} \mathrm{trong} 1 \mathrm{nguyên} \mathrm{tố} \mathrm{của} \mathrm{nguyên} \\ \mathrm{tố} \mathrm{X} \mathrm{là}: \\ \mathrm{A}.7 \mathrm{B}.18 \mathrm{C}.5 \mathrm{D}.9 \\ \mathrm{Câu} 5: \mathrm{Cho} \mathrm{phản} \mathrm{ứng} \mathrm{Al} +{\mathrm{HNO}}_3\to \mathrm{Al}{\left({\mathrm{NO}}_3\right)}_3 +{\mathrm{NH}}_4{\mathrm{NO}}_3+{\mathrm{H}}_2\mathrm{O}. \mathrm{Tổng} \mathrm{hệ} \\ \mathrm{số} (\mathrm{nguyên}, \mathrm{tối} \mathrm{giản}) \mathrm{của} \mathrm{các} \mathrm{chất} \mathrm{trong} \mathrm{phương} \mathrm{trình} \mathrm{sau} \mathrm{khi} \mathrm{cân} \mathrm{bằng} \mathrm{là}: \\ \mathrm{A}.64 \mathrm{B}.58 \mathrm{C}.55 \mathrm{D}.38 \end{gathered}$$