To solve the expression \(9^2 \times 3^{39}\), we can start by simplifying the terms.

First, recognize that \(9\) can be written as \(3^2\). Therefore:
\[9^2 = (3^2)^2\]

Using the power of a power property \((a^m)^n = a^{m \cdot n}\), we get:
\[(3^2)^2 = 3^{2 \cdot 2} = 3^4\]

Now, substitute \(3^4\) for \(9^2\) in the original expression:
\[3^4 \times 3^{39}\]

Next, use the property of exponents that states \(a^m \times a^n = a^{m+n}\):
\[3^4 \times 3^{39} = 3^{4+39} = 3^{43}\]

Therefore, the simplified form of the expression \(9^2 \times 3^{39}\) is:
\[3^{43}\]