To solve the equation

\[
\frac{380}{x} - x + \frac{20}{480} = \frac{1380}{x} - x + \frac{20}{480} = 1
\]

we first recognize that this problem appears to have a formatting or typographical error. Each equation component should be consistent. Assuming the equation is actually:

\[
\frac{380}{x} - x + \frac{20}{480} = 1,
\]

we can proceed as follows:

1. Combine the constant term 20/480:

\[
\frac{380}{x} - x + \frac{1}{24} = 1
\]

2. Subtract 1/24 from both sides of the equation to isolate the fraction and the unknown term:

\[
\frac{380}{x} - x = 1 - \frac{1}{24}
\]

Simplify the right-hand side:

\[
1 - \frac{1}{24} = \frac{24}{24} - \frac{1}{24} = \frac{23}{24}
\]

Thus, the equation is:

\[
\frac{380}{x} - x = \frac{23}{24}
\]

3. Multiply through by \( x \) to eliminate the denominator:

\[
380 - x^2 = \frac{23x}{24}
\]

4. Multiply through by 24 to clear the fraction:

\[
24(380) - 24x^2 = 23x
\]

This simplifies to:

\[
9120 - 24x^2 = 23x
\]

5. Rearrange to form a standard quadratic equation:

\[
24x^2 + 23x - 9120 = 0
\]

6. Solve the quadratic equation using the quadratic formula:

\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]

Here \(a = 24\), \(b = 23\), and \(c = -9120\), so:

\[
x = \frac{-23 \pm \sqrt{23^2 - 4 \cdot 24 \cdot (-9120)}}{2 \cdot 24}
\]

Calculate the discriminant:

\[
23^2 - 4 \cdot 24 \cdot (-9120) = 529 + 873600 = 874129
\]

So:

\[
x = \frac{-23 \pm \sqrt{874129}}{48}
\]

Since \( \sqrt{874129} \approx 935 \), we get:

\[
x = \frac{-23 \pm 935}{48}
\]

This yields two possible solutions:

\[
x = \frac{-23 + 935}{48} = \frac{912}{48} = 19
\]

and

\[
x = \frac{-23 - 935}{48} = \frac{-958}{48} \approx -19.9583
\]

Given the context of \( x \) as a solution subject to \( \frac{380}{x} \), negative values aren’t typically valid (since \( x \) must usually be positive to be within the domain). Therefore, the primary solution is:

\[
x = 19
\]

Thus, \( x = 19 \) is the solution.