To find the sum of the series \( 1 + 3 + 5 + \ldots + 59 \), we recognize that this is an arithmetic series of odd numbers.

The formula for the sum \( S_n \) of the first \( n \) odd numbers is given by:

\[
S_n = n^2
\]

where \( n \) is the count of odd numbers in the series.

To determine \( n \), we observe the last term in our series is \( 59 \). The \( n \)-th odd number can be represented as \( 2n - 1 \). Setting this equal to \( 59 \):

\[
2n - 1 = 59
\]

Solving for \( n \):

\[
2n = 60 \\
n = 30
\]

Now substituting \( n = 30 \) into the formula for the sum of the first \( n \) odd numbers:

\[
S_{30} = 30^2 = 900
\]

Thus, the sum of the series \( 1 + 3 + 5 + \ldots + 59 \) is:

\[
\boxed{900}
\]