PTHH: CaO+2HCl→CaCl2+H2OCaO+2HCl→CaCl2+H2O  (1)

           CaCO3+2HCl→CaCl2+H2O+CO2↑CaCO3+2HCl→CaCl2+H2O+CO2↑  (2)

a) Ta có: nCO2=4,4822,4=0,2(mol)=nCaCO3nCO2=4,4822,4=0,2(mol)=nCaCO3

⇒mCaCO3=0,2⋅100=20(g)⇒mCaCO3=0,2⋅100=20(g) ⇒%mCaCO3=2025,6⋅100%=78,125%⇒%mCaCO3=2025,6⋅100%=78,125%

⇒%mCaO=21,875%⇒%mCaO=21,875%

b) Theo 2 PTHH: ⎧⎪⎨⎪⎩nHCl(2)=2nCaCO3=0,4molnHCl(1)=2nCaO=2⋅25,6−2056=0,2mol{nHCl(2)=2nCaCO3=0,4molnHCl(1)=2nCaO=2⋅25,6−2056=0,2mol

⇒ΣnHCl=0,6mol⇒ΣnHCl=0,6mol ⇒C%HCl=0,6⋅36,5210⋅1,05⋅100%≈9,93%