Two cars, travelling at 62 km/h and 54 km/h respectively, left Town A for Town B at the same time. The faster car passed an oncoming truck 10 hour. An hour after that, the slower car and the struck also passed each other. Find the speed of the struck

A.80KM/H B.60 KM/H C.26KM/H D 116KM/H

Distance traveled by the car A in 10 hours  =  62 (10)

  =  620 km

Distance traveled by the car B in 10 hours  =  54 (10)

  =  540 km

At that time when car A meets the truck, car B will be at 80 km away from both car A and truck.

In order to meet both car B and truck, they will together travel 80 km. Time taken is 1 hour.

Let x be the speed of the truck.Since they are travelling in the opposite direction, the relative speed will be 54 + x.

1  =  80 / (54 + x)

54 + x  =  80

x  =  80 - 54

x  =  26