3x-2/3 = -5x-2/7 = 3-7x/2

It looks like you have a set of equations that you're trying to express. Let's start by separating them out into parts for clarity. From your expression, we have:

1. \(\frac{3x - 2}{3} = -\frac{5x + 2}{7}\)
2. \(\frac{3 - 7x}{23} = -\frac{5x + 2}{7}\)
3. \(\frac{3 - 7x}{23} = \frac{-5x - 2}{7}\) (assuming this is similar to the previous one)

Let's solve each of these equations one at a time.

### Equation 1
\[
\frac{3x - 2}{3} = -\frac{5x + 2}{7}
\]

Cross-multiply to eliminate the fractions:
\[
7(3x - 2) = -3(5x + 2)
\]
Expanding both sides gives:
\[
21x - 14 = -15x - 6
\]
Now, rearranging the equation:
\[
21x + 15x = -6 + 14
\]
\[
36x = 8
\]
Thus,
\[
x = \frac{8}{36} = \frac{2}{9}
\]

### Equation 2
\[
\frac{3 - 7x}{23} = -\frac{5x + 2}{7}
\]

Cross-multiply:
\[
7(3 - 7x) = -23(5x + 2)
\]
Expanding both sides gives:
\[
21 - 49x = -115x - 46
\]
Rearranging yields:
\[
21 + 46 = -115x + 49x
\]
\[
67 = -66x
\]
Thus,
\[
x = -\frac{67}{66}
\]

### Final Check
The last equation you wrote:
\[
\frac{3 - 7x}{23} = \frac{-5x - 2}{7}
\]
This equation is similar to the one we've solved, thus \(x = -\frac{67}{66}\) is consistent.

### Summary of Solutions
1. From the first equation, we found \(x = \frac{2}{9}\)
2. From the second and third equations, we found \(x = -\frac{67}{66}\)

The problem presents conflicting results depending on the equations you are solving. Please clarify or provide additional context if these results don't align with your expectations!