To solve the equation, we can start by isolating the absolute value term:

| x + y + 2 | = - (3x + 3)^2022

Since the absolute value of any real number is always non-negative, the right side of the equation must be non-negative as well. However, the right side is raised to an even power, so it will always be non-negative. Therefore, for the equation to hold, the right side must be equal to zero:

(3x + 3)^2022 = 0

Solving this equation, we find:

3x + 3 = 0
x = -1

Now, substituting x = -1 back into the original equation, we have:

| -1 + y + 2 | = 0

Simplifying, we get:

| y + 1 | = 0

Since the absolute value of any real number is zero only when the number itself is zero, we have:

y + 1 = 0
y = -1

Therefore, the solution to the equation is x = -1 and y = -1.

To find b = x^2022 + y^2023, we substitute the values of x and y into the expression:

b = (-1)^2022 + (-1)^2023

Since (-1)^n is equal to 1 when n is even and -1 when n is odd, we have:

b = 1 + (-1)
b = 0

Therefore, b = 0.