The sum of the arithmetic series 2, 4, 6, ..., 36, 60 can be found using the formula for the sum of an arithmetic series:

Sn = (n/2)(a1 + an)

where Sn is the sum of the series, n is the number of terms, a1 is the first term, and an is the last term.

In this case, the first term a1 is 2, the last term an is 60, and the number of terms n can be found using the formula for the nth term of an arithmetic series:

an = a1 + (n-1)d

where d is the common difference between terms.

In this case, the common difference d is 2 (since each term increases by 2), and we need to find the value of n when an = 60:

60 = 2 + (n-1)2
60 = 2 + 2n - 2
60 = 2n
n = 30

Now we can substitute these values into the formula for the sum of an arithmetic series:

Sn = (n/2)(a1 + an)
Sn = (30/2)(2 + 60)
Sn = 15(62)
Sn = 930

Therefore, the sum of the arithmetic series 2, 4, 6, ..., 36, 60 is 930.