To solve the equation \(3x + 1 - 193 = 2.5^2[99^{100} + 2(10.1234)^3]^0\), let's break it down step by step.

First, simplify the right-hand side of the equation:

1. **Exponentiation and constants:**
\[
2.5^2 = 6.25
\]

2. **Simplifying the expression inside the brackets:**
\[
[99^{100} + 2(10.1234)^3]^0
\]
Any non-zero number raised to the power of 0 is 1:
\[
[99^{100} + 2(10.1234)^3]^0 = 1
\]

3. **Combining the results:**
\[
6.25 \times 1 = 6.25
\]

Now, substitute this back into the original equation:
\[
3x + 1 - 193 = 6.25
\]

Next, simplify the left-hand side:
\[
3x + 1 - 193 = 3x - 192
\]

So the equation becomes:
\[
3x - 192 = 6.25
\]

To isolate \(3x\), add 192 to both sides:
\[
3x = 6.25 + 192
\]
\[
3x = 198.25
\]

Finally, solve for \(x\) by dividing both sides by 3:
\[
x = \frac{198.25}{3}
\]
\[
x \approx 66.0833
\]

So, the solution to the equation is:
\[
x \approx 66.0833
\]